AP Physics - Chapter 7 - #24






Work Energy Theorem



A 60.0-kg skier with an initial speed of 12.0 m/s coasts up a 2.50-m-high rise as shown in Figure 7.37. Find her final speed at the top, given that the coefficient of friction between her skis and the snow is 0.0800. (Hint: Find the distance traveled up the incline assuming a straight-line path as shown in the figure.)

KE=12mv2
PE=mgh

KEinitial+Wnon-conservative=KEfinal+PEgravity
(12mvo2)+(fd)=(12mvf2)+(mgh)
(12mvo2)+((μmg)(hsin(θ)))=(12mvf2)+(mgh)
(12mvo2)+(μgcot(θ)h)=(12mvf2)+(mgh)
(12mvf2)=(12mvo2)+(μgcot(θ)h)(mgh)
12mvf2=12mvo2+μgcot(θ)hmgh
(12mvf2)(12m)=(12mvo2)(12m)+(μgcot(θ)h)(12m)(mgh)(12m)
vf2=vo2+2(μgcot(θ)hm)2gh
vf2=vo2+2gh(1+μcot(θ))
vf=vo2+2gh(1+μcot(θ))
vf=(12.0 m/s)2+2(9.8 m/s2)(2.5 m)(1+μcot(θ))
vf=9.46 m/s