AP Physics - Chapter 7 - #24






Work Energy Theorem



A 60.0-kg skier with an initial speed of 12.0 m/s coasts up a 2.50-m-high rise as shown in Figure 7.37. Find her final speed at the top, given that the coefficient of friction between her skis and the snow is 0.0800. (Hint: Find the distance traveled up the incline assuming a straight-line path as shown in the figure.)

KE=12∗m∗v2
PE=m∗g∗h

KEinitial+Wnon-conservative=KEfinal+PEgravity
(12∗m∗vo2)+(−f∗d)=(12∗m∗vf2)+(m∗g∗h)
(12∗m∗vo2)+((−μ∗m∗g)∗(hsin(θ)))=(12∗m∗vf2)+(m∗g∗h)
(12∗m∗vo2)+(μ∗g∗cot(θ)∗h)=(12∗m∗vf2)+(m∗g∗h)
(12∗m∗vf2)=(12∗m∗vo2)+(μ∗g∗cot⁡(θ)∗h)−(m∗g∗h)
12∗m∗vf2=12∗m∗vo2+μ∗g∗cot⁡(θ)∗h−m∗g∗h
(12∗m∗vf2)(12∗m)=(12∗m∗vo2)(12∗m)+(μ∗g∗cot⁡(θ)∗h)(12∗m)−(m∗g∗h)(12∗m)
vf2=vo2+2∗(μ∗g∗cot⁡(θ)∗hm)−2∗g∗h
vf2=vo2+2∗g∗h∗(1+μ∗cot⁡(θ))
vf=vo2+2∗g∗h∗(1+μ∗cot⁡(θ))
vf=(12.0 m/s)2+2∗(9.8 m/s2)∗(2.5 m)∗(1+μ∗cot⁡(θ))
vf=9.46 m/s